Worth 25 points on my exam
2 answers:
Initial velocity=20m/s Final velocity=0m/s(As the car stops) Acceleration=-8m/s^2 Distance=s=26m We need to verify the thrid equation of kinematics here
The squirrel has a good luck ,Car gets stopped just 1m away from the squirrel .
Explanation:
<u>According</u> <u> to</u> <u> the</u> <u> Question</u>
A squirrel runs out in front of a car moving at +20m/ s ( initial speed u) . The driver slams on the brakes and begins decreasing at - 8 m / s² ( here the acceleration is acting in opposite directions of motion a )
When Squirrel was 2 6 metres ( Distance from the car initially )
Using Kinematic Equation
On substituting the value we obtain
➥ 0² = 20² + 2 × -8 × s
➥ 0 = 400 - 16 × s
➥ -400 = -16 × s
➥ 400/16 = s
➥ 25 = s
So, the squirrel is 2 5 metres from the car .
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C- 10ft. Hope this helped. Have a great day! :D
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