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2 years ago

12

a ramp measures 6 feet long. if the ramp is 12 inches tall, what is the horizontal distance it covers? i'll give brainliest to w

hoever answers first/correctly!

2 answers:

miv72 [106K]2 years ago

8 0

Answer:

6.08 or so

Step-by-step explanation:

The height is 1 foot, while the length is 6 feet.

You can use the Pythagorean Theorum to solve this, as you plug in the values.

The theorum states that A squared plus B squared = C squared, where A is the length, and B is the width. (It doesn't matter if A is the width and B is the length either.)

So if we plug in the values:

1 squared plus 6 squared = C squared.

1 + 36 = 37

Since it is C squared, we can find the square root of 37, which is something like 6.0827625302982196889996842452021.

So usually we round to the hundredths place, so we can use 6.08.

luda_lava [24]2 years ago

6 0

we know that

1 ft--------> is equals to 12 in

the ramp is 12 inches tall----------> 1 ft tall

A ramp measures------------------> 6 ft long

applying the Pythagorean theorem

c²=a²+b²

where

c-----> 6 ft long

a----> horizontal distance

b-----> 1 ft tall

a²=c²-b²------> a²=6²-1²-----> a²=35------> a=√35------> a=5.92 ft

the answer is

5.92 ft

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2 years ago

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2 years ago

Give triangle ABC is a right triangle, and angle A is the right angle. If sin(B)=3/5, find the cos(B).

hichkok12 [17]

Answer:

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Step-by-step explanation:

From the question given above, the following data were obtained:

Sine B = 3/5

Cos B =?

Recall:

Sine B = Opposite / Hypothenus

Sine B = 3/5

Therefore,

Opposite = 3

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Next, we shall determine the Adjacent. This can be obtained as follow:

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Adjacent =?

Hypo² = Adj² + Opp²

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Collect like terms

Adj² = 25 – 9

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4 0

2 years ago

A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and

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and flows out at a rate of

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$\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}$

Solve for S(t):

$\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}$

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The left side is the derivative of a product:

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Integrate both sides:

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There's no sugar in the water at the start, so (a) S(0) = 0, which gives

$0=64+C\impleis C=-64$

and so (b) the amount of sugar in the tank at time t is

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Softa [21]

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Step-by-step explanation:

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5 0

2 years ago