Answer:
Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion . In other words, similar triangles are the same shape, but not necessarily the same size. The triangles are congruent if, in addition to this, their corresponding sides are of equal length.
Step-by-step explanation:
The expression that represents the volume, in cubic units, of the shaded region of the composite figure is: A. One-half(14)(10)(8) – π(2.52)(8).
<h3>Expression</h3>
Given:
Base side length=14 and 10 units
Height=8 units
Diameter=5 units
Hence:
Expression= 1-( half 14)(10)(8) - π(2.52)(8)
Expression=1-(7) (10)(8) - π(2.52)(8)
Expression=1- (560)- 63.33
Expression=-559-63.33
Expression=-622.33
Therefore the expression that represents the volume, in cubic units, of the shaded region of the composite figure is: A. One-half(14)(10)(8) – π(2.52)(8).
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Answer:
35 different routes
Step-by-step explanation:
The problem of how many different routes are possible if a driver wants to make deliveries at 4 locations among 7 locations is a combination problem.
Combination problems are usually selection problems, of all or part of a set of options, without considering the order in which options are selected.
The number of combinations of n objects taken r at a time is: ⁿCᵣ
So, the number of ways the driver can make deliveries at 4 locations out of 7 locations of given by
⁷C₄ = 35 different ways.
Hence, 35 different routes are possible to make deliveries at 4 locations out of 7 locations.
Hope this Helps!!!
<h2>
Answer with explanation:</h2>
By considering the given information, we have
Null hypothesis : 
Alternative hypothesis : 
Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.
Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.
; 
Test statistic : 
i.e. 
Degree of freedom : n-1 = 20-1=19
Significance level = 0.01
For two tailed, Significance level 
By using the t-distribution table, the critical value of t =
Since , the observed t-value (7.25) is greater than the critical value (2.861) .
So we reject the null hypothesis, it means we have enough evidence to support the alternative hypothesis.
We conclude that there is some significance difference between the mean score for sober women and 35.0.
