Answer:
They will sound together at 2pm
Step-by-step explanation:
Now, the first thing we need to calculate is , in how many minutes will the two gongs strike together.
To be able to do this, we need to calculate the least common multiple of the two numbers 24 and 40
The lowest common multiple between both is 120
This means that the two gongs will sound together at exactly 120 minutes
Now since 1 hour is 60 minutes, this means that 120 minutes will be = 120/60 = 2 hours
Since they both sounded together at 12 noon and the next time they will be sounding is next two hours, their sounding time will thus be 12 noon + 2 hours = 2 pm
Answer:
8x = 136
Where: x = 17
Step-by-step explanation:
Joshua is writing a novel. He wrote the same number of pages each day for a 8 days. At the end of 8 days he had 136 pages complete. Write an equation relating x, the number of days, to y, the total pages.
Let the number of pages read per day = x
Hence, the number of pages after 8 days = 8 × x = 8x
Total number of pages = y= 136
Therefore:an equation relating x, the number of days, to y, the total pages.
= 136 = 8x
Solving for x
136/8 = x
x = 17
Answer:
-16
Step-by-step explanation:
y = mx
-4 = 1/4x
Divide both sides by 1/4.
-16 = x
There are 168 hours in one week.
Hope this helps! >.<
Answer:
Incomplete question
Complete question;
A group of eight golfers paid $430 to play a round of golf . Of the golfers one was a member and 7 were not.
Another group of golfers consists of two members and one nonmember. They paid a total of $75. What is the cost for a member to play a round of golf, and what is the cost for a nonmember?
Answer: X = $82.695 for members
Y = $49.615 for non members
Step-by-step explanation:
Let's use X to denote members and Y for non-members.
Therefore, amount paid by one member to play + amount paid by 7 non-members to play = 430
X + 7Y = 430. . .1
Amount paid by 2 members to play + amount paid by one non-member to play = 215
2X + Y = 215. . .2
Solving both equations simultaneously
X+7Y = 430
2X +Y = 215
Therefore, from eqn 1. X = 430-7y
Substituting this into wan 2 gives
2(430-7Y) + Y = 215
860-14Y + Y = 215
860-215 =13Y
645 = 13y
Y = 49.615
Therefore substituting Y = 49.615 into any equation above
X + 7(49.615) = 430
X = 430-347.05
X = 82.695
