Answer:
0.19
Step-by-step explanation:
We are given that
Number of rolls of die=n=1000
Let the event of six coming up be success.Then, in each trial , the probability of success =p=P(success)=P(6)=
Let X be the random variable for the number of sixes in the 1000 rolls of die.
Then,
Since, n is very large,the binomial random variable can be approximated as normal random variable.
Mean,
Variance=
=
=
=0.9977-0.0793=0.9184
Thus, the probability that the number 6 appears between 150 to 200 times=0.92
Now, given that 6 appears exactly 200 times .
Therefore, other number appear in other 800 rolls .
We have to find the probability that the number 5 will appear less than 150 times.
Therefore, for 800 rolls, let the event of 5 coming up be success.
Then , p=P(success)=P(5)=
Let Y be the random variable denoting the number of times 5 coming up in 800 rolls.
Then,
Mean,
Variance,
because n is large
Hence, the probability that the number 5 will appear less than 150 times given that 6 appeared exactly 200 times=0.19