Any number in the form of a+-bi, where a and b are real numbers and b is not equal to 0 is considered a pure imaginary number

2 answers:

7 0

Wrong those are considered complex numbers. pure imaginary numbers have ,0 for a and are thus in the form. 3i, -2i, 17i. etc

NISA [10]2 years ago

4 0

Answer:

<h2>False.</h2>

Step-by-step explanation:

A pure imaginary number is a complex number that doesn't have a real part.

So, if a is a real number, and it doesn't specify that a is only equal to zero, then the expression a+bi is not a pure imaginary number, it's only a complex number. Examples of imaginary numbers are $2i;3i;4i;....bi$ where $b\inR$

In this case, $a\in R$ , that is, a can be $0, \±1, \±2, \±3, ...$

Therefore the statement is false, because a can take any real value.

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