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2 years ago

I need help on this and if you the first person to get it right i will give you BRANLIST

Mathematics

2 answers:

svlad2 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Since x is squared, that's a non-linear equation because it's the only answer that, when graphed, doesn't form a straight line

irga5000 [103]2 years ago

3 0

Letter d. Hope that helps

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Which expression below is equivalent to 2x + 8?

mash [69]

Answer: D) x+4+x+4

The two x terms combine to x+x = 2x

The other pair of like terms, the constants, add to 4+4 = 8

Overall we get 2x+8

2x+8 is also equivalent to 2(x+4) when you factor out the GCF 2.

7 0

2 years ago

P( x) =x^3-6x^2-5x-14 What is the remainder R when the polynomial p(x) is divided by (x-7)

Igoryamba

Answer:

The remainder is zero

Step-by-step explanation:

To find the remainder we will use the long division

$\frac{x^{3}-6x^{2}-5x-14}{x-7}=x^{2}\frac{x^{2}-5x-14 }{x-7}$ ⇒(1)

$\frac{x^{2}-5x-14}{x-7}=x\frac{2x-14}{x-7}$ ⇒(2)

$\frac{2x-14}{x-7}=2$ ⇒(3)

From (1) , (2) and (3)

The quotient of the long division is $x^{2}+x+2$ and no remainder

So the remainder is zero

* If you want to check your answer Multiply the quotient by the divisor

$(x^{2}+x+2)(x-7)=x^{3}-6x^{2}-5x-14$

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2 years ago

What is the discriminant of the quadratic equation, 4x^2-8x-5=0

uysha [10]

Answer:

Step-by-step explanation:

4x^2-8x-5=0

The discriminant is the number under the √. In this case it's 144

7 0

2 years ago

Read 2 more answers

Find the equation of the line that passes through (1, -1) and is parallel to

daser333 [38]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1$

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2 years ago

Solve the system using multiplication for the linear combination method.

zysi [14]

(2,3) is your answer for the equation

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2 years ago

I need help on this and if you the first person to get it right i will give you BRANLIST​

I need help on this and if you the first person to get it right i will give you BRANLIST