Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12
or
y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)
(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)
SOLUTION - GIVEN = Sara has two bag with 60% & 28% peanut.
prove = How much the peanut is used to make 10 pound of 45%
peanut.
TO PROOF - Assume that
let x be the value of the peanut used by sara from the bag
60% peanut bag.
let ( 10 - x) be the value of peanut used by sara from 28% peanut
bag.
as given the bag become of the 10 pound which contain
45% of peanunt.
thus we have
0.60x + 0.28 ( 10 - x ) = 0.45 (10)
0.60x + 0.28 ( 10 -x ) = 4.5
0.60x + 2.8 - 0.28 x = 4.5
0.60x - 0.28x = 4.5 - 2.8
0.32x = 1.7
x = 5.3125 peanut is taken from the 60% bag.
& 4.6875 peanut from the 28% bag.
Where is the following? please complete the question so i could answer you
The answer to your question is 5