Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility
1 answer:
Answer: The solubility of this compound in pure water is 0.012 M
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as
The equation for the ionization of the is given as:
By stoichiometry of the reaction:
1 mole of gives 1 mole of
and 2 mole of
When the solubility of is S moles/liter, then the solubility of
will be S moles\liter and solubility of
will be 2S moles/liter.
Thus solubility of this compound in pure water is 0.012 M
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25.9 kJ/mol. (3 sig. fig. as in the heat capacity.)
<h3>Explanation</h3>The process:
.
How many moles of this process?
Relative atomic mass from a modern periodic table:
- K: 39.098;
- N: 14.007;
- O: 15.999.
Molar mass of :
.
Number of moles of the process = Number of moles of dissolved:
.
What's the enthalpy change of this process?
for
. By convention, the enthalpy change
measures the energy change for each mole of a process.
.
The heat capacity is the least accurate number in these calculation. It comes with three significant figures. As a result, round the final result to three significant figures. However, make sure you keep at least one additional figure to minimize the risk of rounding errors during the calculation.