Answer:
-All the F1 individuals will be pink with medium-width leaves.
-The F2 plants can be:
1/16 red flowers, broad leaves
2/16 red flowers, medium-width leaves
1/16 red flowers, narrow leaves
2/16 pink flowers, broad leaves
4/16 pink flowers, medium-width leaves
2/16 pink flowers, narrow leaves
1/16 white flowers, broad leaves
2/16 white flowers, medium-width leaves
1/16 white flowers, narrow leaves
Explanation:
When there is incomplete dominance, the heterozygous genotype produces a phenotype that's intermediate between the homozygous ones.
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<u>In the case of flower color:</u>
- RR: red
- Rr: pink
- rr: white
<u />
<u>In the case of leaves width:</u>
- BB: broad
- Bb: medium-width
- bb: narrow
A cross between a red-flowered, broad-leaved plant (RRBB) is crossed with a white-flowered, narrowleaved one (rrbb). The homozygous dominant plant only produces RB gametes, and the homozygous recessive plant only produces rb gametes.
-- All the F1 individuals will be heterozygous for both genes (RrBb) and will therefore be pink with medium-width leaves.
The F2 is a result of a F1xF1 cross. Each F1 individual produces the gametes RB, Rb, rB and rb. The possible genotypes and phenotypes arising from the combination of those gametes are:
1/16 RRBB: red flowers, broad leaves
2/16 RRbB: red flowers, medium-width leaves
1/16 RRbb: red flowers, narrow leaves
2/16 rRBB: pink flowers, broad leaves
4/16 rRbB: pink flowers, medium-width leaves
2/16 rRbb: pink flowers, narrow leaves
1/16 rrBB: white flowers, broad leaves
2/16 rrbB: white flowers, medium-width leaves
1/16 rrbb: white flowers, narrow leaves
