Step-by-step explanation:
2x(squared)+9x+9=—1
2x(squared)+9x+9+1=0
2x(squared)+9x+10=0
multiply the coefficient of x and 10=2x10=20
2x(squared)+9x+10=0
look for two numbers that when added gives 9and when multiplied gives 20
2x(squared)+5x+4x+10=0
(2x(squared)+5x)+(4x+10)=0
find the number and letters that are common in the equations
x(2x+5)+2(2x+5)=0
(x+2) (2x+5)=0
x+2=0
collect like terms
x=0-2
x=-2
2x+5=0
collect like terms
2x=0-5
2x=-5
divide both sides by 2
2x/2=-5/2
x=-5/2
so x=-2 and -5/2
Answer:
18.3%
Step-by-step explanation:
Answer:
Hence the probability of the at least 9 of 10 in working condition is 0.3630492
Step-by-step explanation:
Given:
total transistors=100
defective=20
To Find:
P(X≥9)=P(X=9)+P(X=10)
Solution:
There are 20 defective and 80 working transistors.
Probability of at least 9 of 10 should be working out 80 working transistors
is given by,
P(X≥9)=P(X=9)+P(X=10)
<em>{80C9 gives set of working transistor and 20C1 gives 20 defective transistor and 100C10 is combination of shipment of 10 transistors}</em>
P(X≥9)=
<em>(Use the permutation and combination calculator)</em>
P(X≥9)=(231900297200*20/17310309456440)
+(1646492110120/17310309456440)
P(X≥9)=0.267933+0.0951162
P(X≥9)=0.3630492
Answer:
that's the answer man ur welcome btw