Explain which method to use in 4x^2-27=0
2 answers:
Answer:
4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)
So if we have 4x^2 - 27 = 0 then by using the square root properties we get:
4x^2 = 27
x^2= 27/4
x= +/- sqrt(27/4)
x=+/- 3*sqrt(3)/(2)
hope this helps! any questions please just ask! Thank you!!
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