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2 years ago

Choose all of the answers that are correct when describing this atom.

Chemistry

2 answers:

valentinak56 [21]2 years ago

7 0

Answer:

This atom is chlorine.

The mass of this atom is 35 amu.

This atom has an overall charge of 0.

ExplanatiI GOT IT RIGHT

gregori [183]2 years ago

4 0

I believe that this atom is chlorine and the atom has an overall charge of zero.
Chlorine is chemical element which is atomic number 17 in the periodic table. Each chlorine atom has 17 protons (positively charged) in the nucleus balanced by 17 electrons (negatively charged) in the energy shells ( thus an overall charge of zero)

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Using words, explain all steps of dimensional analysis when converting 6.7 hectometers to meters. You must explain the set up of

sleet_krkn [62]

Answer:

See below

Explanation:

In order to convert 6.7 hectometers to meters using dimensional analysis, you must use the ratio of hectometers to meters.

There are 100 meters in one hectometer, then you start setting the equality: 100 m = 1 hm.

Dividing both sides by 1 hm you get the fraction form of the ratio, with meters (m) in the numerator and hectometers (hm) in the denominator.

$1m/100hm$

Since hm is in the numerator, when you multiply 6.7 hm by the unit ratio the hm will be canceled and the result will have only m:

$6.7hm\times 1m/100hm=0.067m$

6 0

2 years ago

Determine the AMOUNT OF NO2, LIMITING REACTANT, AND THE AMOUNT AND NAME OF EXCESS REACTANT.

zepelin [54]

Answer:

balanced equation mole ratio 5 2 mol NO/1 mol O2

10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2

20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO

actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.

Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO

Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2

Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

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2 years ago

What is happening when an oxygen molecule is formed from two separate oxygen atoms?

Pepsi [2]

They share four electrons, two from each oxygen atom

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2 years ago

How many molecules of H2O are equivalent to 97.2g H2O

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2 years ago

H2SO4 + 2NaNO2 → 2HNO2 + Na2SO4

dem82 [27]

<h3>Answer:</h3>

23.459 g NaNO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN] H₂SO₄ + 2NaNO₂ → 2HNO₂ + Na₂SO₄

[Given] 24.14714 g Na₂SO₄

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol Na₂SO₄ = 2 mol NaNO₂

Molar Mass of Na - 22.99 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of Na₂SO₄ - 2(22.99) + 32.07 + 4(16.00) = 142.05 g/mol

Molar Mass of NaNO₂ - 22.99 + 14.01 + 2(16.00) = 69.00 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 24.14714 \ g \ Na_2SO_4(\frac{1 \ mol \ Na_2SO_4}{142.05 \ g \ Na_2SO_4})(\frac{2 \ mol \ NaNO_2}{1 \ mol \ Na_2SO_4})(\frac{69.00 \ g \ NaNO_2}{1 \ mol \ NaNO_2})$
Multiply/Divide: $\displaystyle 23.4587 \ g \ NaNO_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We need 5 sig figs (instructed).</em>

23.4587 g NaNO₂ ≈ 23.459 g NaNO₂

8 0

2 years ago

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