Answer:
yes you are totally right
Let say the point is inside the cylinder
then as per Gauss' law we have
here q = charge inside the gaussian surface.
Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.
we will calculate the charge first which is given as
now using the equation of Gauss law we will have
now we will have
Now if we have a situation that the point lies outside the cylinder
we will calculate the charge first which is given as it is now the total charge of the cylinder
now using the equation of Gauss law we will have
now we will have
It acquires a charge through electrons.
Hope this helps!!!^_~!!!
We can only corelate the object's weight with the amount of water it was able to displaced.
If the water displaced was around 400N, then the amount of liter displaced is around 400 N (kg*m/s²) / 9.8 m/s² (earth's gravitational pull) which is equals to ~40.81 liters which should be the objects mass as the best assumption (1kg = 1L). As there is no direct link between the water displaced and actual object weight.