Answer:
An attraction between two objects that have mass :)
Theories
If it’s wrong oh well because I just guest buh glad to help :)
-- There's a force of 240N pushing her backwards.
-- She's maintaining a steady speed (of 2.5 m/s) .
-- In order to maintain a steady speed (no acceleration),
the forces on her must be balanced. So she's maintaining
a steady force of 240N forward.
-- Every time she moves 1 m forward, she does work of
(force) x (distance) = 240 joules.
-- She moves 2.5 meters forward every second.
So she's doing (240 x 2.5) = 600 joules of work every second.
-- 600 joules per second = 600 watts .
3.75kmper squ hr
acc = (v - u) /t
=(54-32)/8
=22/8
= 3.75kmhr^-2
Explanation:
It is given that,
Initial speed of the automobile, u = 65 km/hr =
Final speed of the automobile, v = 0
Deceleration of the automobile, 
We need to find the distance covered by the car as it comes to rest. It can be calculated using third equation of motion as :
So, the acceleration of the car is 
. Hence, this is the required solution.
