Answer:
A
Step-by-step explanation:
It's obviously the real answer
Answer:
a) 66
b) 45
Step-by-step explanation:
We have 12 horses and after the first race 2 of them have to be eliminated
that condition is equal to consider that 10 horses will be available for the second race.
The number of possiblities we have for the first race is the combination of 12 horses in group of 10
C¹²₁₀ = 12!/ (2!)* (12-2)! = 12*11/2 = 66
For the second race
C¹⁰₈ = 10! / 8! * (10-8)! = 10*9/ 2 = 45
Since 15409-1=15408 and 15408+1=15409, we can write that as one. With 15409-2, we can write the same thing with 15407+2
Answer:
12 dollers and 50 cents
Step-by-step explanation: