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2 years ago

PLEASE HELPPP NEED IT BAD GOD BLESS YOU PLSS

Chemistry

1 answer:

mojhsa [17]2 years ago

5 0

Answer:

Let Me Bless You And Pray For You Dear Jesus Bless This Kid With The Right Answer He Needs You Help Him Please Father Do So Please.

Explanation:

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Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to o

Viefleur [7K]

Answer:

$P_2=404 kPa$

Explanation:

Hello,

In this case, the Boyle's is mathematically defined via:

$P_1V_1=P_2V_2$

Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:

$V_2=\frac{1}{4} V_1$

We can compute the new pressure:

$P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa$

Which means the pressure is increased by a factor of four.

Regards.

7 0

2 years ago

How many lead (Pb) atoms are in a 5.32 g sample of pure lead?

Elanso [62]

Answer:

1.55×10²² molecules.

Explanation:

We'll begin by calculating the number of mole in 5.32 g of pure lead (Pb). This can be obtained as follow:

Mass of Pb = 5.32 g

Molar mass of Pb = 207 g/mol

Mole of Pb =?

Mole = mass /molar mass

Mole of Pb = 5.32/207

Mole of Pb = 0.0257 mole

Finally, we shall determine the number of molecules in 0.0257 mole of Pb. This can be obtained as follow:

From Avogadro's hypothesis,

I mole of Pb contains 6.02×10²³ molecules.

Therefore, 0.0257 mole will contain = 0.0257 × 6.02×10²³ = 1.55×10²² molecules.

Therefore, 5.32 g of pure lead (Pb) contains 1.55×10²² molecules.

4 0

2 years ago

Which of the following are compounds? (Select all that apply.)<br> CO2<br> Cl2<br> Ne<br> NaCl

beks73 [17]

CO2 and NaCl are both compounds

8 0

2 years ago

Match the set of measurements of the boiling point of water with the best

Mashcka [7]

Answer:

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Explanation:

6 0

2 years ago

When using ion-selective electrodes, to compensate for a complex or unknown matrix, the _____________ method can be used to dete

VMariaS [17]

When using ion-selective electrodes, to compensate for a complex or unknown matrix, the standard addition method can be used to determine the analyte concentration. Option D

<h3>What are ion-selective electrodes?</h3>

Analytical chemistry is a science that deal with the measurement and detection of the accurate amount of a substance. Analytical chemistry plays a large role in environmental management as it helps in the determination of the levels of contaminants in a sample.

An ion selective electrode is used in analytical chemistry to measure the amount of a target ion by converting its activity into a measurable electrical signal.

Hence, when using ion-selective electrodes, to compensate for a complex or unknown matrix, the standard addition method can be used to determine the analyte concentration.

Learn more about ion-selective electrodes:brainly.com/question/14987024

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7 0

1 year ago