Dimethylformamide
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<h2>1.25 g of 
would be produced from the complete reaction of 25 mL of 0.833 mol/L 
with excess 
</h2>
Explanation:
To calculate the number of moles for given molarity, we use the equation:
According to stoichiometry:
1 mole of will give = 1 mole of
0.0208 moles of will give =
of
Mass of
Thus 1.25 g of would be produced from the complete reaction of 25 mL of 0.833 mol/L
with excess
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