Ask question

Ask question

All categories

Citrus2011 [14]

2 years ago

14

PLEASE HELP I NEED THE ANSWER ASAP

1 answer:

Andreas93 [3]2 years ago

7 0

Answer:

x>3, the last option with the open circle

Step-by-step explanation:

You might be interested in

If A(7,9) and B(3,12) find AB (remember: AB means "the distance between points A and B")

GREYUIT [131]

The length of segments ab is 24

5 0

2 years ago

3 /10 4/ 8 which one is bigger?

Olegator [25]

Answer:

4/8

Step-by-step explanation:

3/10 is 0.30 and 4/8 is 0.5

6 0

2 years ago

F(x) = x + 4 and g(x) = 2x + 3, evaluate each expression.

Rom4ik [11]

Answer:

$15.~f(g(2))=\Large\boxed{11}\\$

$16.~g(f(2.5))=\Large\boxed{16}$

$17.~g(f(-5))=\Large\boxed{1}$

$18.~f(g(-5))=\Large\boxed{-3}$

Step-by-step explanation:

<h3>Given information</h3>

$f(x)=x+4$

$g(x)=2x+3$

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

$g(2)=2(2)+3$

$g(2)=4+3$

$g(2)=7$

<u>Substitute the values of the first function into the second</u>

$f(g(2))=f(7)$

$f(7)=(7)+4$

$f(7)=\Large\boxed{11}$

<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

$f(2.5)=(2.5)+4$

$f(2.5)=6.5$

<u />

<u>Substitute the values of the first function into the second</u>

$g(f(2.5))=g(6.5)$

$g(6.5)=2(6.5)+3$

$g(6.5)=13+3$

$g(6.5)=\Large\boxed{16}$

<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

$f(-5)=(-5)+4$

$f(-5)=-1$

<u>Substitute the values of the first function into the second</u>

$g(f(-5))=g(-1)$

$g(-1)=2(-1)+3$

$g(-1)=-2+3$

$g(-1)=\Large\boxed{1}$

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

$g(-5)=2(-5)+3$

$g(-5)=-10+3$

$g(-5)=-7$

<u>Substitute the values of the first function into the second</u>

$f(g(-5))=f(-7)$

$f(-7)=(-7)+4$

$f(-7)=\Large\boxed{-3}$

Hope this helps!! :)

Please let me know if you have any questions

7 0

1 year ago

Helpppp meeeee plssss

Diano4ka-milaya [45]

DONT open file it’s a scam and tracker please don’t open it

3 0

2 years ago

The rate at which sand is poured into a bag is modeled by the function r given by r(t)=15t−2t2, where r(t) is measured in millil

balu736 [363]

Answer:

35 mililiters

Step-by-step explanation:

Given

$r(t) = 15t - 2t^2$

Required

Accumulated amount from t = 0 to 2

This implies that, we substitute the values of t from 0 to 2 in the function

$r(0) = 15*0 - 2*0^2= 0$

$r(1) = 15*1 - 2*1^2= 13$

$r(2) = 15*2 - 2*2^2= 22$

The accumulated sand (r) is:

$t = r(0) + r(1) + r(2)$

$r = 0 + 13 + 22$

$r = 35$

6 0

2 years ago