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2 years ago

9

For the given domain value fill in the Y value for the equation Y=2/3x-3

1 answer:

Sveta_85 [38]2 years ago

4 0

Y=2/3 times x/1-3
=y=2x/3-3
y=2/3x-3

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A coffee shop sold 72 large cups of coffee on Monday. Each large cup of coffee cost $4.35.

frez [133]

Answer:

314 large cups

Step-by-step explanation:

72x4.35=313.2

6 0

2 years ago

Read 2 more answers

Find the measure of each of the angles. Don’t forget to label your answer

user100 [1]

Answer:

$a=125^o$

$b=55^o$

$c=55^o$

$d=55^o$

$e=125^o$

$f=55^o$

Step-by-step explanation:

step 1

Find the value of x

we know that

$(2x+25)^o=(x+75)^o$ ----> by alternate interior angles

solve for x

Group terms

$2x-x=75-25$

$x=50$

step 2

Find the measure of angle a

we know that

$a=(x+75)^o$ ----> by vertical angles

substitute the value of x

$a=(50+75)=125^o$

step 3

Find the measure of angle b

we know that

$a+b=180^o$ ----> by supplementary angles (form a linear pair)

we have

$a=125^o$

substitute

$125^o+b=180^o$

$b=180^o-125^o=55^o$

step 4

Find the measure of angle c

we know that

$c=b$ ----> by vertical angles

we have

$b=55^o$

therefore

$c=55^o$

step 5

Find the measure of angle d

we know that

$d=b$ ----> by corresponding angles

we have

$b=55^o$

therefore

$d=55^o$

step 6

Find the measure of angle e

we know that

$e=a$ ----> by alternate exterior angles

we have

$a=125^o$

therefore

$e=125^o$

step 7

Find the measure of angle f

we know that

$f=d$ ----> by vertical angles

we have

$d=55^o$

therefore

$f=55^o$

4 0

2 years ago

I need help with the photo below.

PSYCHO15rus [73]

Here, 30/360 * 2πr = 10
1/12 * 2 * 3.14 * r = 10
r = 10*12 / 6.28
r = 19.11

Now, Area = 1/12 * 3.14 * (19.11)²
= 3.14/12 * 365.16
= 95.5 Ft²

In short, Your Answer would be Option C

Hope this helps!

3 0

2 years ago

Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

1 year ago

Whats the measure of

maxonik [38]

Acute angle i think about 60

8 0

2 years ago