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2 years ago

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Chemistry

1 answer:

Natalka [10]2 years ago

3 0

Explanation:

To find the amount of product that would be formed from two or more reactants, we need to follow the following steps;

Find the number of moles of the given reactants.
Then proceed to determine the limiting reactant. The limiting reactant is the one in short supply which determines the extent of the reaction.
Use the number of moles of the limiting reactant to find the number of moles of the product.
Then use this number of moles to find the mass of the product

Useful expression:

Mass = number of moles x molar mass

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What is the single replacement reaction of Zinc + Lead(iv) Chloride

ExtremeBDS [4]

Answer:

$2Zn+PbCl_4\rightarrow 2ZnCl_2+Pb$

Explanation:

Hello there!

In this case, when referring to single replacement reactions, it is crucial for us to figure out the formula of the starting reactants; thus, we know zinc is Zn and lead (IV) chloride is PbCl₄. In such a way, the reaction proceeds as follows:

$Zn+PbCl_4\rightarrow ZnCl_2+Pb$

Which must be balanced as shown below:

$2Zn+PbCl_4\rightarrow 2ZnCl_2+Pb$

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strojnjashka [21]

If it is a true or false questions, the answer is TRUE.

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A chemist prepares a solution of copper(II) fluoride by measuring out of copper(II) fluoride into a volumetric flask and filling

Simora [160]

The question is incomplete, here is the complete question.

A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.

Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

<u>Explanation:</u>

To calculate the molarity of solute, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of copper (II) fluoride = 0.0498 g

Molar mass of copper (II) fluoride = 101.54 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$\text{Molarity of copper (II) fluoride)=\frac{0.0498\times 1000}{101.54\times 100.0}\\\\\text{Molarity of copper (II) fluoride}=4.90\times 10^{-3}mol/L$

Hence, the concentration of copper fluoride in the solution is $4.90\times 10^{-3}mol/L$

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2 years ago

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andrezito [222]

Answer:

Molecularity of the rate determining step = 2

Explanation:

Step 1 (slow): H₂O₂ + I⁻ -----> H₂O + OI⁻

Step 2 (fast): H₂O₂ + OI⁻ -----> H₂O + O₂ + I⁻

The rate determining step in a reaction mechanism is also considered as slowest step.

Slowest step is also considered its highest activation energy in energy profile diagram.

In this case intermediate (IO⁻) is formed.

Step 1 considered as a slowest step.

So, Rate = K [H₂O₂][I⁻]

Molecularity = 2

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