Answer is: 5,75·10⁻¹.
Kf = 2,3·10⁶ 1/s.
K = 4,0·10⁸ 1/s.
Kr = ?
Kf - <span>forward rate constant.
K - </span><span>equilibrium constant.
Kr - </span><span>reverse rate constant.
</span>Since both Kf and Kr are constants at a given temperature, their ratio is also a constant that
is equal to the equilibrium constant K.<span>
K = Kf/Kr.
Kr = Kf/K = </span>2,3·10⁶ 1/s ÷ 4,0·10⁸ 1/s = 5,75·10⁻¹.
Answer:
?
Explanation:
can you describe the question a little more please?
Answer:
The reactions free energy
Explanation:
From the question we are told that
The pressure of (NO) is
The pressure of (Cl) gas is
The pressure of nitrosly chloride (NOCl) is
The reaction is
⇆
From the reaction we can mathematically evaluate the (Standard state free energy ) as
The Standard state free energy for NO is constant with a value
The Standard state free energy for is constant with a value
The Standard state free energy for is constant with a value
Now substituting this into the equation
The pressure constant is evaluated as
Substituting values
The free energy for this reaction is evaluated as
Where R is gas constant with a value of
T is temperature in K with a given value of
Substituting value
Answer:
Reagents: 1) 2) ,
Mechanism: Hydroboration
Explanation:
In this case, we have a <u>hydration of alkene</u>s reaction. But, in this example, we have an <u>anti-Markovnikov reaction</u>. In other words, the "OH" is added in the least substituted carbon. Therefore we have to choose an anti-Markovnikov reaction: <u>"hydroboration"</u>.
The <u>first step</u> of this reaction is the addition of borane () to the double bond. Then in the <u>second step</u>, we have the deprotonation of the hydrogen peroxide, to obtain the peroxide anion. In the <u>third step</u>, the peroxide anion attacks the molecule produced in the first step to produce a complex compound in which we have a bond "". In <u>step number 4</u> we have the migration of the C-B bond to oxygen. Then in <u>step number 5</u>, we have the attack of on the to produce an alkoxide. Finally, the water molecule produce in step 2 will <u>protonate</u> the molecule to produce the alcohol.
See figure 1
I hope it helps!
Ernest Rutherford i believe