(NH₄)₂S
%N= 41.18%
%H =11.76%
%S=47.06%
Mg(NO₃)₂
%Mg=32.43%
%N=18.92%
%O=(64.86%
<h3>Further explanation</h3>
Given
(NH₄)₂S
Mg(NO₃)₂
Required
The percent composition
Solution
(NH₄)₂S MW=68 g/mol
%N=2. Ar N / MW (NH₄)₂S x 100%
%N= (2.14/68) x 100% = 41.18%
%H =(8.1/68) x 100%=11.76%
%S=(32/68)x 100%=47.06%
Mg(NO₃)₂ MW=148 g/mol
%Mg=(2.24/148)x100%=32.43%
%N=(2.14/148)x100%=18.92%
%O=(6.16/148)x100%=64.86%
Answer:
Heat is a measure of the flow of thermal energy from one object or substance to another. ... Thermal energy typically flows from a warmer material to a cooler material. Generally, when thermal energy is transferred to a material, the motion of its particles speeds up and its temperature increases.
Explanation:
Answer:
Explanation:
- For the balanced reaction:
<em>4Fe(s) + 3O₂(g) → 2Fe₂O₃(s).</em>
It is clear that 4 mol of Fe react with 3 mol of O₂ to produce 2 mol of Fe₂O₃.
- Firstly, we need to calculate the no. of moles of 35.8 grams of Fe metal:
no. of moles of Fe = mass/molar mass = (35.8 g)/(55.845 g/mol) = 0.64 mol.
- Now, we can find the no. of moles of O₂ is needed to react with the proposed amount of Fe:
<em><u>Using cross multiplication:</u></em>
4 mol of Fe is needed to react with → 3 mol of O₂, from stichiometry.
0.64 mol of Fe is needed to react with → ??? mol of O₂.
∴ The no. of moles of O₂ needed = (3 mol)(0.64 mol)/(4 mol) = 0.48 mol.
- Finally, we can get the volume of oxygen using the information:
<em>It is known that 1 mole of any gas occupies 22.4 L at standard P and T (STP).</em>
<em></em>
<em><u>Using cross multiplication:</u></em>
1 mol of O₂ occupies → 22.4 L, at STP conditions.
0.48 mol of O₂ occupies → ??? L.
∴ The no. of liters of O₂ = (0.48 mol)(22.4 L)/(1 mol) = 10.752 L.
