The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
<em><u>Solution:</u></em>
Given that,
<em><u>We have to substitute eqn 1 in eqn 2</u></em>
Substitute x = 2.1925 in eqn 1
y = 2.1925 + 3
y = 5.1925
Substitute x = -3.1925 in eqn 1
y = -3.1925 + 3
y = -0.1925
Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)
I have no clue but I think it’s 959583”04&6&(9;
Mark reads about 350 (D) wpm
Explanation:
700 words x 10 pages= 7000 words
7000 words/ 20 minutes
= 350 wpm
D. 8 grams
The equation
Ending Amount = Beginning Amount / 2(time / half-life)
32/2^(6/3)
32/2^2
32/4
=8