(x+2)(x+8) = x^2 +10x +16
(x^2 + 10x + 16)(x-1) = x^3+9x^2+6x-16, so the other dimension is x-1
Answer:
comment the question I will try to solve it.....
Answer:
4 people
Step-by-step explanation:
Let's first write an equation.
We want to find the number of tickets t
The total was $49 so our equation will equal $49 and they spent $15 in snacks so on the other side of the eqaution we have to add $15, on the same side as the snacks we need to add in the cost of tickets, which is $8.50 multiplies by t, or the total number of tickets.
$49 = $8.50t + $15
Solve for t, first subtract $15 from both sides.
$49 - $15 = $8.50t
$34 = $8.50t Divide both sides by $8.50
$34/$8.50 = $8.50t/$8.50
$34/$8.50 = t
4 = t
4 tickets meaning 4 people went.
The function is discrete, as the fee is charged based on the hours
