The radius is 6
Complete the square on the equation and get
(x-6)^2 + (y-6)^2 =36
The circle equation is
(x-h)^2 + (y-k)^2 = r^2
Center(h,k) r=radius
Answer:
1. x/5
2. cubed root of 2x
3.x-10
4.(2x/3)-17
Step-by-step explanation:
Answer:
first we get y on one side by itself.
4x+5y=5
we'll move x to the other side.
4x-4x+5y=5-4x
simplify.
5y=5-4x
now we get rid of the coefficient on y.
5y/5=(5-4x)/5
simplify.
y=5/5-4x/5
y=1-
The answer is
3x-13=305
3x=305+13
3x=318
(3x)÷3=318÷3
x=106
check.. (3×106)-13=305
318-13=305
305=305
Answer:
The set of polynomial is Linearly Independent.
Step-by-step explanation:
Given - {f(x) =7 + x, g(x) = 7 +x^2, h(x)=7 - x + x^2} in P^2
To find - Test the set of polynomials for linear independence.
Definition used -
A set of n vectors of length n is linearly independent if the matrix with these vectors as columns has a non-zero determinant.
The set is dependent if the determinant is zero.
Solution -
Given that,
f(x) =7 + x,
g(x) = 7 +x^2,
h(x)=7 - x + x^2
Now,
We can also write them as
f(x) = 7 + 1.x + 0.x²
g(x) = 7 + 0.x + 1.x²
h(x) = 7 - 1.x + 1.x²
Now,
The coefficient matrix becomes
A =
Now,
Det(A) = 7(0 + 1) - 1(7 - 7) + 0
= 7(1) - 1(0)
= 7 - 0 = 7
⇒Det(A) = 7 ≠ 0
As the determinant is non- zero ,
So, The set of polynomial is Linearly Independent.