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2 years ago

Given: G = 6.67259 × 10−11 N m2 /kg2

Physics

1 answer:

8_murik_8 [283]2 years ago

8 0

Answer:

Work done W 2.938*10^9 J

Explanation:

given data:

mass m = 944 Kg

Mass of moon M = 7*10^22 Kg

Radius of the moon R = 1.5*10^6 m

gravitational constant G = 6.67*10^{-11} Nm^2/Kg^2

we know that work done is given as

Work done $W = \frac{GMm}{R}$

$= \frac{6.67*10^{-11}*7*10^{22}*944}{1.5*10^6 m}$

= 2.938*10^9 J

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A disk of radius 10 cm speeds up from rest. It turns 60 radians reaching an angular velocity of 15 rad/s. What was the angular a

Kruka [31]

Answer: α = 1.875 rad/s²

Explanation:

ω₁² = ω₀² + 2αθ

ω₀ = 0

α = ω₁² / 2θ

α = 15² / 2(60)

α = 1.875 rad/s²

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2 years ago

Precipitation clouds are observed at a distance of about 720 miles to the west of a city. The clouds are seen moving westwards a

tankabanditka [31]

This question may require more information for an accurate answer. If the clouds are observed west of the city and they are moving in a westerly direction it means that the clouds are moving away. Precipitation refers to rainfall, sleet, hail or snow. Since no reference was made to the temperature, season or location of the city it could be rain or snow clouds. The clouds are moving away from the city so the possible answers could be b. or d. Furthermore, by dividing the distance by the speed one would get an answer of twenty four hours. So even if the clouds were moving towards the city it would take a day to reach and precipitation would not be likely in 24 hrs.

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3 years ago

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A glass ball of radius 3.74 cm sits at the bottom of a container of milk that has a density of 1.04 g/cm3. The normal force on t

Gelneren [198K]

Answer:

The mass of the ball is 0.23 kg

Explanation:

Given that

radius ,r= 3.74 cm

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Normal force ,N= 9.03 x 10⁻² N

The volume of the ball V

$V=\dfrac{4}{3}\pi r^3$

$V=\dfrac{4}{3}\times \pi \times 3.74^3\ cm^3$

V= 219.13 cm³

The bouncy force on the ball = Fb

Fb = ρ V g

Fb + N = m g

m=Mass of the ball = Density x volume

m = γ V , γ =Density of the Ball

ρ V g + N = γ V g ( take g= 10 m/s²)

$\gamma =\dfrac{N+\rho V g}{V g}$

$\gamma =\dfrac{9.03\times 10^{-2}+1.04\times 10^{-3}\times 219.13\times 10}{219.13\times 10}$

γ = 0.00108 kg/cm³

m = γ V

m = 0.00108 x 219.13

m= 0.23 kg

The mass of the ball is 0.23 kg

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2 years ago

4748.36242611007 round to the nearest tenth

IceJOKER [234]

Answer:4748.36

Explanation:

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2 years ago

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Which FBD would represent a car moving right with a motor force of 250 N, and force of friction of 750N, a weight of 8500N and a

babymother [125]

Answer:

Option C

Explanation:

Given that

Motor force is 250 N

Force of friction is 750 N

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And, the normal force is 8500 N

Now based on the above information

Here length of the rector shows the relative magnitude forward force i.e. 250 N i..e lower than the frictional force i.e. backward and weight i.e. 8500 would be equivalent to the normal force

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2 years ago