The frequency of this wave is 3
Answer:
891 excess electrons must be present on each sphere
Explanation:
One Charge = q1 = q
Force = F = 4.57*10^-21 N
Other charge = q2 =q
Distance = r = 20 cm = 0.2 m
permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)
Using Coulomb's law,
F=[1/4pieo]q1q2/r^2
F = [1/4pieo]q^2 / r^2
q^2 =F [4pieo]r^2
q = r*sq rt F[4pieo]
q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]
q = 1.42614*10^ -16 C
number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19
n =891
891 excess electrons must be present on each sphere
because as the distance increases the gravitational force decreases so the weight of a body decreases
Answer:
v = 6.06 m/s
Explanation:
In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:
where,
v = minimum speed of motorcycle at top of the loop = ?
g = acceleration due to gravity = 9.8 m/s²
r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m
Therefore, using these values in equation, we get:
<u>v = 6.06 m/s</u>
Answer:
part A ⇒ u = 1.28 m
part B ⇒v = 0.43 m
Explanation:
for u is the distance to the object from the mirror and v is the distance from the mirror to the image.
Part A:
the mirror equation is given by:
1/f = 1/v + 1/u
but we told that, v = 1/3u:
1/f = 3/v + 1/u = 4/u
1/f = 4/u
f = u/4
u = 4f
= 4×(32×10^-2)
= 1.28 m
Therefore the distance from the mirror to the object is 1.28 m.
part B:
v = 1/3×u = 1/3×(1.28) = 0.43 m
