Answer:
The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.
Explanation:
Given that,
Initial velocity u= 128 ft/sec
Equation of height
....(I)
(a). We need to calculate the maximum height
Firstly we need to calculate the time
From equation (I)
Now, for maximum height
Put the value of t in equation (I)
(b). The number of seconds it takes the object to hit the ground.
We know that, when the object reaches ground the height becomes zero
Hence, The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.
By definition we have to:
Applied force: It is the external force that acts directly on a body.
Therefore, we can say that if you have an object and push it towards yourself, you are exerting an external force on the object.
This external force was not acting on the object previously, therefore, it is a force that you are applying at that moment.
Answer:
you exert an Applied Force on an object when you pull it towards you
A. Applied Force
That they sometimes explode?
Answer:
Fa = 5000 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
Let's assume that the movement of the plane is to the right, any movement or force to the right will be marked with a positive sign, while any force or movement to the left, will be taken as negative.
The force of the turbine drives the plane to the right, therefore it is positive, the acceleration is constant and keeps the movement to the right, therefore it is positive, the wind drag force tries to prevent the movement of the plane to the left therefore it is negative, with this analysis we deduce the following equation.
ΣF = m*a
where:
ΣF = sum of forces [N] (units of Newtons)
m = mass = 65000 [kg]
a = acceleration = 3 [m/s²]
Fa = force exerted by the air [N]
200000 - Fa = 65000*3
Fa = 200000 - (3*65000)
Fa = 5000 [N]