Answer:
The answer is C. 6.4 X 8 in
Step-by-step explanation:
If the scale factor from the original to the trimmed photo is 5:4
The statement above just means the scale of the old dimension is 5 while the scale of the new dimension is 4.
To get the new dimensions, multiply each of the old dimensions by 4/5
4/5 X 10 = 8
4/5 X 8 = 6.4
Therefore the new dimension is 6.4 X 8 in
Answer:
-20
Step-by-step explanation:
it basically -14-6
Answer:
$ 44
Step-by-step explanation:
If we analyze the statement well, we can observe something very crucial to solve it, the jumbo biscuits require 2 oz of flour and give a profit of $ 0.08, the Regular one that only requires 1 oz of flour leaves a profit of $ 0.11, which means that requiring a smaller quantity of flour leaves a greater profit, so in terms of profit it is not profitable to make Jumbo, only Regular.
Therefore, since you can make 400 biscuits, they would all be regular since there are 600 oz of flour available, it is enough to make 400, therefore the maximum profit would be:
$ 0.11 * 400 = 44
The maximum possible profit is $ 44
<em>The answer you are looking for is: </em>
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Answer:
Required volume is 
unit.
Step-by-step explanation:
Given equations of curves,
, 
substitute second in first we will get,
When 
and 
. Thus both curves intersect at the points (4,16),(-4,16). And thus 
.
Considering width of the representative rectangle as 
which is parallel to x-axis because of considering cylindrical shell. Therefore volume of the shell is given by,
Now,
Length of generating box=Length of from line x=4(axis of revolution)=circumference of the shell=(4-x)
Width of box=
Hence,
![=2\pi\{144\big[x\big]_{-4}^{4}-18\big[x^2\big]_{-4}^{4}-\frac{8}{3}\big[x^3\big]_{-4}^{4}+\frac{1}{2}\big[x^4\big]_{-4}^{4}\}](https://tex.z-dn.net/?f=%3D2%5Cpi%5C%7B144%5Cbig%5Bx%5Cbig%5D_%7B-4%7D%5E%7B4%7D-18%5Cbig%5Bx%5E2%5Cbig%5D_%7B-4%7D%5E%7B4%7D-%5Cfrac%7B8%7D%7B3%7D%5Cbig%5Bx%5E3%5Cbig%5D_%7B-4%7D%5E%7B4%7D%2B%5Cfrac%7B1%7D%7B2%7D%5Cbig%5Bx%5E4%5Cbig%5D_%7B-4%7D%5E%7B4%7D%5C%7D)
which is required volume of generating area.
