10.0.0.0/8 is variably subnetted, 3 subnets, 2 masksC10.1.1.0/30 is directly connected, Serial0/0/0L10.1.1.1/32 is directly connected, Serial0/0/0R10.2.2.0/30 [120/1] via 10.1.1.2, 00:00:21, Serial0/0/0172.30.0.0/16 is variably subnetted, 2 subnets, 2 masksC172.30.10.0/24 is directly connected, GigabitEthernet0/1L172.30.10.1/32 is directly connected, GigabitEthernet0/1R3 only displays its own subnets for the 172.30.0.0 network. R3 does not have any routes for the172.30.0.0 subnets on R1.
Answer:
10.7a-8.1b
Step-by-step explanation:
Answer:
-30
Step-by-step explanation:
I used a calculator
<h2>A. -12</h2>
Step-by-step explanation:
<h3 /><h2>A. Is the answer of your math question.</h2>
<h2>Mark me as</h2><h3>#Brainliest Answer</h3>
Its -1,3
<span>y=4<span>x2</span>+8x+7</span>
There is a formula for finding the vertex= <span>y=a<span>x2</span>+bx+c</span>
<span>h=−<span>b<span>2a</span></span></span> and <span>k=c−<span><span>b2</span><span>4a</span></span></span>
Solve for h with <span>a=4</span> and <span>b=8</span> and <span>c=7</span>
<span>h=−<span>b<span>2a</span></span>=<span><span>−8</span><span>2⋅4</span></span>=−1</span>
<span><span>
=</span>−<span>b<span>2a</span></span>=<span><span>−8</span><span>2⋅4</span></span>=−1</span>
Solve for k
<span>k=c−<span><span>b2</span><span>4a</span></span>=7−<span><span>82</span><span>4⋅4</span></span>=7−<span>6416</span>=7−4=3</span>
Our vertex is at <span>(−1,3)</span>
<span>y=4<span>x2</span>+8x+7</span> with vertex at <span>(−1,3)</span>
