Find the common denominator. It’s 10
22 2/10+f=-10 5/10
-22 2/10 -22 2/10
f = -32 7/10
Given:
Quadrilateral ABCD is inscribed in a circle P.
To find:
Which statement is necessarily true.
Solution:
Quadrilateral ABCD is inscribed in a circle P.
Therefore ABCD is a cyclic quadrilateral.
In cyclic quadrilateral, opposite angles form a supplementary angles.
⇒ m∠A + m∠C = 180° --------- (1)
⇒ m∠B + m∠D = 180° --------- (2)
By (1) and (2),
⇒ m∠A + m∠C = m∠B + m∠D
This statement is necessarily true for the quadrilateral ABCD in circle P.
Just substitute r with 357 and solve.
= 1/7(357) + 3(1/7(357))
= 51 + 3(51)
= 51 + 153
= 204
Therefore, Eliza read 204 in those 3 days.
Best of Luck!
Answer: i dont this you can combine like terms for this question because none of these have the same variable or anything.
