Answer:
x = 9.6
Step-by-step explanation:
Before we can figure out what x is, we need to figure out what the unlabeled side is. To figure that out, multiply the hypotenuse (12) by the sine of the angle labeled (34)
12 * sin(34)
<em>sin(34) equals 0.559192903470747; I'll round it to 0.6 for convenience.</em>
12 * 0.6
<em>Now simply multiply 12 by 0.6 to get 7.2.</em>
The unlabeled side is approx. 7.2 units long.
Now we know what the unlabeled side is. Now, to find x, find the square root of 12 squared minus 7.2 squared.
x = √12² - 7.2²
<em>12 squared is 144; 7.2 squared is 51.84.</em>
x = √144 - 51.84
<em>Subtract 51.84 from 144 to get 92.16.</em>
x = √92.16
<em>The square root of 92.16 is 9.6 (on the spot!).</em>
x equals 9.6.
If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
To learn more about normal distribution, click here:
brainly.com/question/4079902
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9x-6+6x-1=98
15x+7=98
15x=105
x=7
hope this helps :)
Answer: 13.7
Step-by-step explanation:
