Answer: Kate = 40/3 Her father = 50
Step-by-step explanation:
Let Kate's age in the present be K
And Kate's father's age in the present be F
3(K+5) = F+5
6(K-6) = F-6
Rearrange the first equation to get
3K+15 = F+5
3K+10 = F
Substitute that into the second question
6K-36 = 3K+10-6
3K = 40
K = 40/3
So F = 3*40/3+10 = 50
Yes. That's correct. Is that what you're asking...? To clarify, prime numbers have a single factor (one and itself) , composite numbers have multiple factors.
Answer:
$61.17
Step-by-step explanation:
Okay so this is the closest answer I could get because 61.17*0.85=51.9945, which is really close to $52.So the answer is really close to $61.17.
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
So the answer choices are
1. a-b=even
2. a and b are not odd
3. a and b are odd
4. a-b=even
5. a-b=not even
even=not odd
not even=odd so choice 5 is really a-b=odd
basically choice 4 and 1 are the same so we cross one out
so
the problem said that a and b are odd so therefor choice2 is wrong and choice 3 is correct
then both are odd
odd-odd=even because
an even number is represented as 2n where n is an integer
an odd number can be represented as 2n+1 so assume you have 2 odd numbers 2 away from each other so odd and (odd+2)
odd+2-odd=2n+1+2-(2n+1)=2n+1+2-2n-1=2n-2n+1-1+2=2
you are left with odd
using integers
7 and 11
11-7=4
even
so odd-odd=even, it depends on weather you consider 0 odd or even
so the asnwers are:
a and b are odd
a-b is not an even integer
