Let S = {1,2,3,4,5,6,7,8,9,10} be the set of equally likely outcomes for an event. Let event E = {1,2,3,4,5,6} and event F = {2,
4,6,8}.
P(E and F^c) P(E or F) P(E) P(E^c or F^c) P(E^c) P(F) P(F^c)
0.3
0.4
0.6
0.7
P(E and F^c) P(E or F) P(E) P(E^c or F^c) P(E^c) P(F) P(F^c)
0.3
0.4
0.6
0.7
1 answer:
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Answer:
1.) It has one solution (–5, 5).
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