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2 years ago

How many cm 3 are in 0.14 m 3?

Chemistry

1 answer:

nlexa [21]2 years ago

5 0

Answer:

There are 14 cm in 0.14 m

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A rock is an example

sveticcg [70]

Answer:

the correct answer is option ( B ) rocks cannot change their volume ,shape, and size

because a solid substance cannot change its, volume, shape and size

Hope it helps you

have a nice day

3 0

2 years ago

Kc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial concentration of NOBr = 0.878 M, what is the equilibrium

pav-90 [236]

Answer:

The equilibrium concentration of NO is 0.02124 M.

Explanation:

Given that,

Initial concentration of NOBr = 0.878 M

$k_{c}=3.07\times10^{-4}$

Temperature = 24°C

We know that,

The balance equation is

$2NOBr\Rightarrow 2NO+Br_{2}$

Initial concentration is,

$0.878\Rightarrow 0+0$

Concentration is,

$-2x\Rightarrow 2x+x$

Equilibrium concentration

$0.878-2x\Rightarrow 2x+x$

We need to calculate the value of x

Using formula of concentration

$k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}$

Put the value into the formula

$3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}$

$2x^2=3.07\times10^{-4}\times(0.878)^2+3.07\times10^{-4}\times4x^2-2\times2x\times0.878\times3\times10^{-4}$

$2x^2=0.0002367+0.001228x^2-0.0010536x$

$2x^2-0.001228x^2+0.0010536x-0.0002367=0$

$1.998772x^2+0.0010536x-0.0002367=0$

$x=0, 0.01062$

We need to calculate the equilibrium concentration of NO

Using formula of concentration of NO

$concentration\ of\ NO=2x$

Put the value of x

$concentration\ of\ NO=2\times0.01062$

$concentration\ of\ NO=0.02124$

Hence, The equilibrium concentration of NO is 0.02124 M.

7 0

3 years ago

5. Which of the following statements is incorrect?

Vikki [24]

Answer:

c- dry cells can not be recharged

6 0

2 years ago

the volume of liquid can be measured with? A. graduated cylinder B. pan balance C. scale D. metric ruler

alina1380 [7]

a: is the correct anwser

6 0

2 years ago

density of a sample of tin is 8 g/'ll when the actual density was 7.28 g/ml. what was the percentage error

riadik2000 [5.3K]

9.9%

|Approximate Value − Exact Value| divided by

|Exact Value| X 100

7 0

2 years ago