<span>D. 20 + 2âš10 units
To solve this, you simply need to calculate the length of each side of the triangle with the vertexes of A(3,4), B(-5,-2), and C(5,-2). The length of each side is simply calculated using the pythagoras theorem. Note that it doesn't matter what order you do the subtraction. The absolute value will be the same and if it happens to be negative, not a problem since it will become positive once you square the values.
So the length of side AB is
sqrt((3-(-5))^2 + (4-(-2))^2) = sqrt(8^2 + 6^2) = sqrt(64 + 36) = sqrt(100) = 10.
The length of side BC is
sqrt((-5 - 5)^2 + (-2 - (-2))^2) = sqrt(-10^2 + 0^2) = sqrt(100+0) = sqrt(100) = 10.
And finally, the length of side AC is
sqrt((3-5)^2 + (4-(-2))^2) = sqrt(-2^2 + 6^2) = sqrt(4+36) = sqrt(40)
= 2 * sqrt(10)
Finally, add all the lengths together.
10 + 10 + 2âš10 = 20 + 2âš10</span>
- Rational
-Irrational
-Rational
-Rational
Just took the test
I don't know domain but range is the smallest number and largest number, median is the middle number when the numbers are ordered from least to greatest, and the mode is the most common or reoccuring variable in a set of numbers.
The answer is 8i.
i = √(-1)
√(-64) = √((-1) * 64)
= √(-1) * √64
= i * √8²
= i * 8
= 8i
Answer:
1. -72
2. -64
Step-by-step explanation:
it is increasing by 4 so,
-76, -72, -68, -64, -60, -56.