Answer:
sorry but you're gonna need to add more info to this question to get an answer
The answer is 0 < x < infinity
I can’t see good this image
Answer:
is outside the circle of radius of 
centered at 
.
Step-by-step explanation:
Let 
and 
denote the center and the radius of this circle, respectively. Let 
be a point in the plane.
Let 
denote the Euclidean distance between point and point .
In other words, if is at 
while is at 
, then 
.
Point would be inside this circle if 
. (In other words, the distance between 
and the center of this circle is smaller than the radius of this circle.)
Point would be on this circle if 
. (In other words, the distance between and the center of this circle is exactly equal to the radius of this circle.)
Point would be outside this circle if 
. (In other words, the distance between and the center of this circle exceeds the radius of this circle.)
Calculate the actual distance between and :
.
On the other hand, notice that the radius of this circle, 
, is smaller than . Therefore, point would be outside this circle.
42-x=58
or, -x=58-42
with change in side sign also chamges we change sides to make like terms in one side and unlike in amother side.
or, -x= 16
or,x=-16.
therefore x=-16...
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>
