Answer:
B) 
x units
Step-by-step explanation:
Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:
Perimeter of a rectangle = 2 (l + b)
where: l is the length = 12 units and b is the breadth = 8 units. So that:
Perimeter of KMPT = 2 (12 + 8)
= 40 units
Dilating KMPT by a scale factor of would create K'M'P'T' of dimensions; × 12 units by × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.
Perimeter of K'M'P'T' = 2 (l + b)
= 2(9 + 6)
= 30 units
Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be × perimeter of KMPT.
Therefore, if the perimeter of KMPT is x units, then;
perimeter of K'M'P'T' = * x units
= x units
Answer:x=x=
−2
5
y+
4
5
Step-by-step explanation:
Let's solve for x.
2y+5x=4
Step 1: Add -2y to both sides.
5x+2y+−2y=4+−2y
5x=−2y+4
Step 2: Divide both sides by 5.
5x
5
=
−2y+4
5
x=
−2
5
y+
4
5
Answer:
x=
−2
5
y+
4
5
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Answer:
=8p−7.25
Step-by-step explanation:
=(5)(p)+(5)(−1)+(3)(p)+(3)(−0.75)
=5p+−5+3p+−2.25
=5p+−5+3p+−2.25
=(5p+3p)+(−5+−2.25)
=8p+−7.25
Answer:
9 (2 a - 3)^2
Step-by-step explanation:
Simplify the following:
(6 a - 9)^2
Hint: | Factor out the greatest common divisor of the coefficients of 6 a - 9.
Factor 3 out of 6 a - 9:
(3 (2 a - 3))^2
Hint: | Distribute exponents over products in (3 (2 a - 3))^2.
Multiply each exponent in 3 (2 a - 3) by 2:
3^2 (2 a - 3)^2
Hint: | Evaluate 3^2.
3^2 = 9:
Answer: 9 (2 a - 3)^2
Answer:
Domain: (-∞, ∞)
Range: (0,∞)
Step-by-step explanation:
Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis unless a value has been added to it. If it has, the curve shifts. This function has addition on the exponent but not to the whole function so it does not change the asymptote. Its y - values remain between 0 and ∞. This is the range, the set of y values.
However, the range of exponentials can change based on the leading coefficient. If it is negative the graph flips upside down and its range goes to -∞. This doesn't have it either.
The addition to 1 on the exponent shifts the function to the left but doesn't change the range.
In exponential functions, the x values are usually not affected and all are included in the function. Even though it shifts, the domain doesn't change either. Its domain is (-∞, ∞).
Domain: (-∞, ∞)
Range: (0,∞)
