Step-by-step explanation:
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Need to FinD :</h3>
- We have to find the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0.
Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.
Where,
- PQ = Opposite side
- QR = Adjacent side
- RP = Hypotenuse
- ∠Q = 90°
- ∠C = θ
As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,
Since, we know that,
- cosθ = 5/13
- QR (Adjacent side) = 5
- RP (Hypotenuse) = 13
So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.
Therefore,
∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.
Where,
- Opposite side = 12
- Hypotenuse = 13
Therefore,
Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.
- By substituting the values, we get,
∴ Hence, the required answer is 17/7.
C, 125. Hope I helped.
btw, u gotta do 35+30+25+20+15
C. 0.0806 that’s the write answer to your equation I think
Answer
2.(2,1)
3. (2,2)
Step-by-step explanation:
Given,
2.2x+y=4
x+3y=_3
sol
2x+y=4..... equation i
x+3y=_3 ....eq ii
eq ii of 2 multiple the eq i
2x+y=4
2x+6y=_6
_ _ +
__________
o+ 5y = 10
y =10÷5
y = 2 ans
y valu put the eq 1
2x+y=4
2x+2=4
2x=4_2
2x=2
x=2÷2
x=1
3.
sol
3x+5y=4..... eq 1
x+3y=4 ..... eq 2
eq 2 multiple eq 1. 3
3x+5y=4
3x+9y=12
_ _ _
___________
0x+4y=8
4y=8
y=8÷4
y=2 ans
the y value put the eq 1
3x+5y=4
3x+5×2=4
3x+10=4
3x=10_4
3x=6
x=6÷3
×=2 ans