Answer:
Increases
Explanation:
The expression for the capacitance is as follows as;
Here, C is the capacitance, is the permittivity of free space, A is the area and d is the distance between the parallel plate capacitor.
It can be concluded from the above expression, the capacitance is inversely proportional to the distance. According to the given problem, the capacitor is disconnected from the battery and the distance between the plates is increased. Then, the capacitance of the given capacitor will decrease in this case.
The expression for the energy stored in the parallel plate capacitor is as follows;
Here, E is the energy stored in the capacitor, C is the capacitance and Q is the charge.
Energy stored in the given capacitor is inversely proportional to the capacitor. The charge on the capacitor is constant. In the given problem, as the distance between the parallel plates is being separated, the energy stored in this capacitor increases.
Therefore, the option (c) is correct.
Answer:
First Law
Explanation:
I learned this in 6th grade
Answer: Subtract the kinetic energy of the block at x=0.02mx=0.02m from the kinetic energy of the block at x=0.00mx=0.00m.
Explanation:
Answer:
t = 39.04 1010 year
Explanation:
This is a nuclear disintegration exercise that is governed by the equation.
N = N0 e (-lam t)
The average life time is related to nuclear activity
T ½ = ln 2 / lam
Let's use these two equations for exercise, let's start by finding nuclear activity
Lam = ln 2 / T ½
Lam = ln 2 / 4.9 10 10
Lam = 0.14146 10-10 y-1
They tell us that the relationship atoms
No / N = 0.0040
Let's look
No / N = 1/0040
N/No = 250
Let's calculate the time
(-lam t) = ln (N / No)
, t = - 1 / lam ln (n / No)
t = - 1 / 0.14146 10-10 ln (250)
t = 39.04 1010 year
Answer:
Magnitude of force the ground exerts on the plow = 263.234 N
Explanation:
Magnitude of force the ground exerts on the plow = Fground - Fplow
We are given that:
Fgound = 275 N
We will now calculate Fplow as follows:
Fplow = mass of horse * acceleration of plow
Fplow = 53 * 0.222
Fplow = 11.766 N
Now, substitute in the above equation to get magnitude of force the ground exerts on the plow as follows:
Magnitude of force the ground exerts on the plow = Fground - Fplow
Magnitude of force the ground exerts on the plow = 275 - 11.766
Magnitude of force the ground exerts on the plow = 263.234 N
Hope this helps :)