Answer: The final temperature of nickel and water is .
Explanation:
The given data is as follows.
Mass of water, m = 55.0 g,
Initial temp, ,
Final temp, = ?,
Specific heat of water = 4.184 ,
Now, we will calculate the heat energy as follows.
q =
=
Also,
mass of Ni, m = 15.0 g,
Initial temperature, ,
Final temperature, = ?
Specific heat of nickel = 0.444
Hence, we will calculate the heat energy as follows.
q =
=
Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.
= -()
=
Thus, we can conclude that the final temperature of nickel and water is .
Answer:
Ionization energy is a measure of the difficulty involved in removing an electron from an atom or ion or the tendency of an atom or ion to surrender an electron.
Explanation:
The answer is: [D]: a reactant.
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Answer: b design procedure
Explanation:
design a procedure
Data:
V1 = 6.7 liter
T1 = 23° = 23 + 273.15 K = 300.15 K
P1 = 0.98 atm
V2 = 2.7 liter
T2 = 125° = 125 + 273.15 K = 398.15 K
P2 = ?
Formula:
Combined law of ideal gases: P1 V1 / T1 = P2 V2 / T2
=> P2 = P1 V1 T2 / (T1 V2)
P2 = 0.98 atm * 6.7 liter * 398.15 K / (300.15K * 2.7 liter)
P2 = 3.22 atm