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2 years ago

Which of the following reactions does the coenzyme biotin catalyze?

Chemistry

1 answer:

Papessa [141]2 years ago

5 0

Answer:

c. decarboxylation of an a-keto acid.

Explanation:

Decarboxylation refers to the removal of the carboxyl group from a carboxylic acid and thus releasing carbon dioxide. Decarboxylases are enzymes that speed up the removal of the carboxyl group from acids. These reactants could be amino acids, alpha-keto acids, and beta-keto acids. Biotin is known to catalyze the decarboxylation of malonyl CoA to acetyl CoA during fatty acid synthesis.

Malonyl CoA is converted to acetyl CoA after decarboxylation assisted by biotin also known as Vitamin H. Alpha keto acids are involved in fatty acids synthesis and Malonyl CoA is an alpha-keto acid because the keto group is located in the first carbon near the carboxylic acid group. Keto acids have both a carboxyl group and a ketone group.

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Risk is the ______ of a negative outcome

Vera_Pavlovna [14]

Is there any choices or is this a fill in the blank question?

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2 years ago

What would the volume of gas be at 150 c if it had a volume of 693 ml at 45 c

marissa [1.9K]

Answer:

$\boxed{\text{922 mL}}$

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

$\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 693 mL; T₁ = 45 °C

V₂ = ?; T₂ = 150 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = ( 45 + 273.15) = 318.15 K

T₂ = (150 + 273.15) = 423.15 K

(b) Calculate the volume

$\dfrac{ 693}{318.15} = \dfrac{ V_{2}}{423.15}\\\\2.178 = \dfrac{ V_{2}}{423.15}\\\\V_{2} = 2.178 \times 423.15 = \boxed{\textbf{922 mL}}$

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2 years ago

C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)<br><br> Which type of reaction is this?

erastova [34]

Answer: Combustion

Explanation:

3 0

4 months ago

An atom of this element has _____ shells and _____ valence electrons.

Dmitry_Shevchenko [17]

Answer:

1 orbital (shells) and 1 valence electron

Explanation:

If an atom of hydrogen is a neutral atom, it will have 1 proton in the nucleus and 1 electron in the electron shell.

4 0

2 years ago

For the balanced equation shown below, if the reaction of 0.112 grams of

Alekssandra [29.7K]

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield= $\frac{actual yield}{theoretical yield}$ x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112 $H_{2}$ x $\frac{1 mol H_{2} }{2.016 g of H{2} }$ x $\frac{4 mol H_{2}O }{4 mol H_{2} }$ x $\frac{18.02 g H_{2}O }{1 mol H_{2}O}$ = 1.001 g $H_{2}O$

Now Step 2

% yield = $\frac{actual yield}{theoretical yield}$ x 100% = $\frac{0.745g}{1.001g}$ = 74.5%

8 0

2 years ago