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2 years ago

Need the answers please help

Mathematics

1 answer:

Aleonysh [2.5K]2 years ago

7 0

Answer:

$\frac{1}{2}x+\frac{6}{5}=\frac{3}{10}x+\frac{3}{20}$

$x=-5\frac{1}{4}$

$7x-3+10=2x-8+8x$

Hope this helps

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- a. Find the common factors of 6 and 9.

Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

Common factors : what make up a number (they will be all prime)

6 - 2, 3

9 - 3,3

the common factor is three (its what they have in common)

3 0

2 years ago

Read 2 more answers

Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?

cluponka [151]

Under the given transformation, the Jacobian and its determinant are

$\begin{cases}x=uv\\y=u^2\end{cases}\implies J=\begin{bmatrix}v&u\\2u&0\end{bmatrix}\implies|\det J|=2u^2$

so that

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\iint_{D'}\frac{2u^2}{u^2}\,\mathrm du\,\mathrm dv=2\iint_{D'}\mathrm du\,\mathrm dv$

where $D'$ is the region $D$ transformed into the $u$ - $v$ plane. The remaining integral is the twice the area of $D'$ .

Now, the integral over $D$ is

$\displaystyle\iint_D\frac{\mathrm dx\,\mathrm dy}y=\left\{\int_0^6\int_{x^2/2}^{x^2}+\int_6^{12}\int_{x^2/2}^{6x}\right\}\frac{\mathrm dx\,\mathrm dy}y$

but through the given transformation, the boundary of $D'$ is the set of equations,

$\begin{array}{l}y=x^2\implies u^2=u^2v^2\implies v^2=1\implies v=\pm1\\y=\frac{x^2}2\implies u^2=\frac{u^2v^2}2\implies v^2=2\implies v=\pm\sqrt2\\y=6x\implies u^2=6uv\implies u=6v\end{array}$

We require that $u>0$ , and the last equation tells us that we would also need $v>0$ . This means $1\le v\le\sqrt2$ and $0$ , so that the integral over $D'$ is

$\displaystyle2\iint_{D'}\mathrm du\,\mathrm dv=2\int_1^{\sqrt2}\int_0^{6v}\mathrm du\,\mathrm dv=\boxed6$

4 0

2 years ago

I need help this is a tangent and secant problem and I'm confused

Luda [366]

<h3>Answer: 110 degrees</h3>

======================================================

Work Shown:

x = measure of minor arc CL

angle J = ( (far arc) - (near arc) )/2

angle J = ((red arc) - (yellow arc))/2

angle J = ( (minor arc CL) - (minor arc CK) )/2

35 = ( x - 40 )/2

35*2 = x-40

70 = x-40

x-40 = 70

x = 70+40

x = 110

Minor arc CL = 110 degrees

8 0

2 years ago

A total of 504tickets were sold for the school play. They were either adult tickets or student tickets. There were 54more studen

LuckyWell [14K]

Answer:

225 adult tickets

Step-by-step explanation:

S: no. of students

A: no. of adults

S = A + 54

S + A = 504

A + A + 54 = 504

2A = 450

A = 225

S = 225 + 54

S = 279

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2 years ago

I NEED THIS ANSWER FAST. Show work.

777dan777 [17]

Answer:

1/20

Step-by-step explanation:

Entire the entire bottle/tube of the treatment.

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2 years ago

Need the answers please help​

Need the answers please help