The graph of a linear relationship has a slope of -5 and passes through the point (2, -12). Write the equation of the line in sl
ope-intercept form.
1 answer:
<h3>Answer:</h3>
y=-5x-2
<h3>Solution:</h3>
- We are given the line's slope and a point that it passes through.
- Using the given information, we can write the equation of the line in Point-Slope Form:
- In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
- In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
- Plug in the values:
- y-(-12)=-5(x-2)
- y+12=-5(x-2)
- Now, convert into Slope-Intercept Form, y=mx+b:
- y+12=-5x+10
- y=-5x+10-12
- y=-5x-2
Hope it helps.
Do comment if you have any query.
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