Answer:
her supply has 18 pounds
Explanation:
Assume that the number of pounds in her supply is x.
We are given that:
She uses 1/3 x in salted mix and 2/9 x in unsalted mix.
This means that:
Total amount used = 1/3 x + 2/9 x = 5/9 x of her supply
Now, we are also given that:
She used 10 pounds of her supply.
This means that:
5/9 x = 10
5x = 9*10 = 90
x = 18 pounds
Hope this helps :)
To find the decimal you divide the number on the top of the fraction by the number on the bottom of the fraction. so...:
258/300=0.86
now, to find the percent, you simply convert the decimal:
0.86 represents 86 hundredths (which is the second place after the decimal point)
which can also be stated at 86%
Dax goes to the store to buy milk. There is a sale for milk, and it now costs 3 dollars since it was 60% off. What was the original price of the milk?
3 - 60
x - 100
Cross multiply
300=60x
5=x
The milk original cost 5 dollars.
Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:
35/40 - 8/40 = 27/40.
I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)
When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:
27/40 * 1/5 = 27/200
So each piece is about 27/200 m in length (or 0.135 m in length).
If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
Answer: No
Step-by-step explanation:
A variable is always denoted with a symbol (commonly x), and a variable means that it can change based on what you plug into the symbol
Constants must always stay the same, so variables can't be constants and constants can't be variables
