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2 years ago

What is a greatest common multiple

1 answer:

3 0

The greatest common multiple the the largest integer that can go into two other integers.
For example.
60 and 75. A common multiple would be five since it can got into both evenly. However, the largest common multiple would be 15, because it is the largest whole number that can go into 60 and 75.
Just in case, an integer is a whole number. No decimals.

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A Rectangular has area 12a^2 and perimeter 14a what are the dimensions of this Rectangular?

Nataliya [291]

9514 1404 393

Answer:

3a by 4a

Step-by-step explanation:

For dimensions L and W, the area and perimeter are ...

A = LW = 12a^2

P = 2(L+W) = 14a

Using the second equation, we can find L:

L +W = 7a . . . . . divide by 2

L = 7a -W

Substituting into the area formula gives the quadratic ...

(7a -W)(W) = 12a^2

W^2 -7aW +12a^2 = 0 . . . . arrange in standard form

(W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)

Then we have the two solutions ...

W = 3a, L = 4a

W = 4a, L = 3a

The rectangle dimensions are 3a by 4a.

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2 years ago

What is a function and how does it work?

liq [111]

For f(3)...put 3 as the value of x in f(x)
for x.....put the value of f(x) from the given and equate it with 14..and solve

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2 years ago

PLEASE HELP ME PLS I NEED IT

SOVA2 [1]

Answer:

X=17.9

Step-by-step explanation:

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2 years ago

The lakeside marina charges a $35 rental fee for a boat in addition to charging $15 per hour. Part D:what information does the i

STALIN [3.7K]

Answer: B.The cost of rental fee only

Step-by-step explanation:

The $35 is the cost of the rental fee only. The person would then have to pay a further $15 for every hour they use the boat.

Essentially, the $35 is the fixed cost associated with the rental and the $15 is the variable cost to do so. If this were in a linear equation format it would take the form: y = 15x + 35.

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1 year ago

Simplify the expression. Write the answer without using parentheses or negative exponents.

rodikova [14]

$\frac{ (x^4 y^2)^5 }{ (x^2 y)^2 } =\frac{ x^{4*5} y ^{2*5} }{ x ^{2*2} y ^2 } =\frac{ x^{20} y ^{10} }{ x^4y^2 } = x^{20-4} *y^{10-2}= x^{16} *y^{8}$

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2 years ago