Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by
The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same
Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
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I think it’s 34 hope this helps
Answer:
no
Step-by-step explanation:
threr is no 9
<span>ΔABC is not a right triangle.</span>
Answer:
I’m not sure what you mean by divided, but the square root of 24 would be between 4 and 5.
Explanation:
I translated 4 and 5 into square roots, being the square root of 16 (4^2) and the square root of 25 (5^2).
4 is equal to the square root of 16 just as 5 is equal to the square root of 25.
Of the given square roots in the answers, only the square root of 24 was between the square roots of 16 and 25. Therefore, the square root of 24 is between 4 and 5.