The image is decomposed as follows: H1 and H2. Where original graph is Hx.
<h3>Are the images (attached) valid decompositions of the original graph?</h3>
- Yes, they are because, H1 and H1 are both sub-graphs of Hx; also
- H1 ∪ H2 = Hx
- They have no edges in common.
Hence, {H1 , H2} are valid decomposition of G.
<h3>What is a Graph Decomposition?</h3>
A decomposition of a graph Hx is a set of edge-disjoints sub graphs of H, H1, H2, ......Hn, such that UHi = Hx
See the attached for the Image Hx - Pre decomposed and the image after the graph decomposition.
Learn more about decomposition:
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Answer:
The answer to your question is:
Step-by-step explanation:
Data
f(x) = -2x² + 8x - 2
Process
-2x² + 8x = y + 2
-2(x² - 4x + 4) = y + 2 - 8
-2(x - 2)² = y - 6
(x - 2)² = 1/2 (y - 6)
Vertex = (2, 6)
Axis of symmetry = x = 2
y-intercept
f(0) = -2(0)² + 8(0) - 2
f(0) = 0 + 0 - 2
f(0) = -2
Domain (-∞, ∞)
Range (-∞, 6]
See the graph below
Answer:
$0.75
Step-by-step explanation:
28.50-24=$4.50
4.50/6=$0.75
Answer:
the original price was $46.12
Step-by-step explanation:
if you add 5 back to that number.