(√5 + 3)² / √20=
((√5 + 3)² / √20)(√20/√20)=
(√20(√5 + 3)²) / (√20)²=
√20(5+6√5+9) /20=
√20 (14+6√5) /20=
(14√20 +6√100) /20=
(14√20 +60) / 20=
(14(√4√5) + 60) /20=
(14(2)(√5)+60) / 20=
(28√5+60) /20=
(7√5+15) / 5
Answer:(√5 + 3)² / √20= <span>(7√5+15) / 5</span>
Answer:
A1 / B1 ;
(D1 - A1) / B1 ;
(A1 - E1*A1) / B1
Step-by-step explanation:
A1 = original price of car
B1 = annual Depreciation amount
Number of years it will take for the car to depreciate totally :
Using the straight line Depreciation relation :
y = mx + c
c = intercept = initial or original value of car
m = annual Depreciation amount
x = number of years
y = value after x years
For total Depreciation, final value, y = 0
0 = mx + c
mx = - c
x = - c / m
Hence, x = A1 / B1
B.)
D1 = car value
Length it will take for car to depreciate to value in D1 :
y = mx + c
y = D1; m = B1 ; c = A1
D1 = B1x + A1
B1x = D1 - A1
x = (D1 - A1) / B1
C.)
E1 = decrease percentage
Time it takes for car to decrease by percentage in E1
y = E1 * A1
E1 * A1 = B1x + A1
(A1 - E1*A1) = B1x
x = (A1 - E1*A1) / B1
Incorrectly? U wanna get it wrong ?
Answer:
From $1600 to $3400.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 2500
Standard deviation = 300
What interval of dealer incentives would we expect approximately 99.7% of vehicles to fall within?
By the Empirical Rule, 99.7% fall within 3 standard deviations frow the mean. So
From 2500 - 3*300 = 1600 to 2500 + 3*300 = 3400.